Frequency Distribution

Key Concepts

Solved Examples: 62

Practice Questions: 5

Solved Examples
A. Marks and their frequencies arranged in a table
B. Marks arranged in ascending order with frequencies
C. Marks recorded exactly as collected without any arrangement
D. Marks grouped into class intervals
Therefore, the correct answer is Option C.
Which type of frequency distribution is most suitable?
A. Grouped frequency distribution
B. Ungrouped frequency distribution
C. Cumulative frequency distribution
D. Relative frequency distribution
Since the number of distinct observations is small, an ungrouped frequency distribution is sufficient.
Therefore, the correct answer is Option B.
A. 0
B. 5
C. 12
D. 4.5
Since 4.5 is not a whole number, it cannot represent a frequency.
Therefore, the correct answer is Option D.
10–20
20–30
30–40
What is the problem with these class intervals?
Similarly, 30 belongs to both the second and third intervals.
This creates overlapping class intervals, causing ambiguity while classifying observations.
Therefore, the class intervals are not mutually exclusive and should be modified appropriately.
3, 6, 8, 5 and 4.
Without knowing the actual observations, what is the total number of observations?
= 3 + 6 + 8 + 5 + 4
= 26
Question 6: Can an observation have a frequency of 0? Explain.
A frequency of 0 means that the observation does not occur in the data set.
For example, if the observations are 5, 6 and 8, then the frequency of 7 is 0 because it is absent from the data.
Therefore, a frequency of 0 is valid and indicates that the observation is not present.
| Books Read | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| Frequency | 6 | 11 | 9 | 7 |
Which observation occurs most frequently?
This corresponds to the observation 2.
Therefore, the observation that occurs most frequently is 2.
| Reading Hours | 1 | 2 | 3 |
|---|---|---|---|
| Frequency | 4 | 4 | 7 |
Can two different observations have the same frequency?
Frequency indicates how many times an observation occurs.
In the table above, the observations 1 and 2 both have a frequency of 4.
Therefore, two or more different observations can have the same frequency.
2, 1, 3, 2, 0, 2, 1, 4, 3, 2, 1, 2, 3, 0, 2
Find the frequency of the observation 2.
Therefore, Frequency of 2 = 6
| Fruit | Apple | Banana | Orange | Mango |
|---|---|---|---|---|
| Frequency | 15 | 18 | 11 | 18 |
Which fruits are equally popular?
Therefore, these two fruits are equally popular.
| Observation | A | B | C | D |
|---|---|---|---|---|
| Frequency | 9 | 12 | 11 | ? |
Find the missing frequency.
= 9 + 12 + 11
= 32
Missing frequency
= 40 − 32
= 8
2, 3, 1, 2, 4, 3, 2, 1, 3, 2, 4, 3
Prepare an ungrouped frequency distribution table.
| Goals Scored | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| Frequency | 2 | 4 | 4 | 2 |
The sum of frequencies = 2 + 4 + 4 + 2 = 12, which matches the total number of observations.
| Number of Pets | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| Frequency | 6 | 10 | 8 | 3 |
Find the total number of families surveyed.
= 6 + 10 + 8 + 3
= 27
| Day | Monday | Tuesday | Wednesday | Thursday |
|---|---|---|---|---|
| Tally Marks | ||||/ | ||||/ || | ||| | |||| |
Find the total number of customers.
Tuesday = 7
Wednesday = 3
Thursday = 4
Total customers = 5 + 7 + 3 + 4 = 19
12, 18, 15, 22, 25, 27, 31, 34, 18, 24, 29, 35, 21, 17, 26, 38, 14, 19, 33, 28
Prepare a grouped frequency distribution using the class intervals:
10–19, 20–29, 30–39
| Class Interval | 10–19 | 20–29 | 30–39 |
|---|---|---|---|
| Frequency | 7 | 8 | 5 |
Question 16: The total number of observations is 40.
| Class Interval | 0–9 | 10–19 | 20–29 | 30–39 |
|---|---|---|---|---|
| Frequency | 8 | 12 | ? | 9 |
Find the missing frequency.
= 8 + 12 + 9
= 29
Missing frequency
= 40 − 29
= 11
Question 17: Find the class width of the class interval 40–49.
= 49 − 40 + 1
= 10
10–19, 20–29, 30–39, 40–?
Find the missing upper class limit.
Therefore, the last class interval should be: 40–49
Hence, the missing upper class limit is 49.
| Number of Children | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| Frequency | 5 | 13 | 9 | 7 |
By how many does the frequency of families with 2 children exceed that of families with 1 child?
Frequency of 1 child = 5
Difference = 13 − 5 = 8
| Observation | 5 | 6 | 7 | 8 |
|---|---|---|---|---|
| Frequency | 3 | 3 | 2 | 1 |
Identify the error.
5 appears 4 times.
6 appears 3 times.
7 appears 2 times.
8 appears 1 time.
The frequency of 5 has been recorded incorrectly.
It should be 4, not 3.
| Books Read | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Frequency | 5 | 8 | 10 | 6 | 3 |
Number of such students
= 10 + 6 + 3
= 19
∴ 19 students
| Goals Scored | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| Frequency | 2 | 7 | 9 | 6 | 4 |
Number of matches
= 2 + 7 + 9
= 18
∴ 18 matches
| Number of Siblings | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| Frequency | 3 | 9 | 12 | 5 | 1 |
Number of students
= 3 + 9 + 12
= 24
∴ 24 students
| Mode of Transport | Bus | Bicycle | Walk | Car |
|---|---|---|---|---|
| Tally Marks | ||||/ ||| | ||||/ | | |||| | ||| |
| Frequency | ? | ? | ? | ? |
Bicycle = 5 + 1 = 6
Walk = 4
Car = 3
∴ Frequencies = 8, 6, 4 and 3
| Number of Pets | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| Tally Marks | ||| | ||||/ || | ||||/ | |||| |
| Recorded Frequency | 3 | 7 | 4 | 4 |
But the recorded frequency is 4.
∴ The error is in the frequency for 2 pets.
Correct frequency = 5.
12, 18, 24, 15, 31, 27, 19, 34, 22, 16, 29, 25, 13, 37, 21, 28, 17, 33, 26, 14
Prepare a grouped frequency distribution using the class intervals 10–19, 20–29 and 30–39.
| Class Interval | 10–19 | 20–29 | 30–39 |
|---|---|---|---|
| Frequency | 8 | 8 | 4 |
Sum of frequencies = 8 + 8 + 4 = 20
∴ The frequency distribution accounts for all 20 observations.
21, 24, 27, 23, 29, 31, 26, 22, 25, 28, 32, 24, 27, 30, 23, 26, 29, 21, 25, 33, 28, 24, 31, 27
Prepare a grouped frequency distribution using the class intervals 20–24, 25–29 and 30–34.
| Temperature (°C) | 20–24 | 25–29 | 30–34 |
|---|---|---|---|
| Frequency | 8 | 11 | 5 |
Sum of frequencies = 8 + 11 + 5 = 24
∴ The frequency distribution accounts for all 24 observations.
35, 42, 51, 27, 63, 48, 55, 39, 72, 44, 58, 31, 67, 52, 46, 75, 28, 61
Prepare a grouped frequency distribution using the class intervals 20–39, 40–59 and 60–79.
| Pages Read | 20–39 | 40–59 | 60–79 |
|---|---|---|---|
| Frequency | 4 | 8 | 6 |
Sum of frequencies = 4 + 8 + 6 = 18
∴ The frequency distribution accounts for all 18 observations.
A. 0–10, 11–20, 21–30, 31–40, 41–50
B. 0–9, 10–19, 20–29, 30–39, 40–49
C. 0–10, 10–20, 20–30, 30–40, 40–50
D. 1–10, 11–20, 21–30, 31–40, 41–50
Cover the required range without gaps.
Have equal widths.
Avoid overlapping.
Option A covers 0 to 50 using five equal-width intervals of 10 marks.
∴ Correct answer = Option A
A. 12–21, 22–31, 32–41, 42–51, 52–61
B. 12–20, 21–30, 31–40, 41–50, 51–61
C. 10–20, 20–30, 30–40, 40–50, 50–60
D. 12–22, 23–33, 34–44, 45–55, 56–66
Option A gives five intervals, each containing 10 integer values:
12–21, 22–31, 32–41, 42–51, 52–61
∴ Correct answer = Option A
A. 1–10, 11–20, 21–30
B. 1–9, 10–19, 20–30
C. 1–10, 10–20, 20–30
D. 1–11, 12–21, 22–30
Option A gives three equal-width intervals 1–10, 11–20, 21–30
∴ Correct answer = Option A
For example, the first class contains 10, 11, 12, …, 19
∴ Class width = 10
1–10, 11–20, 21–30, 31–40, 41–50
∴ Number of classes = 5
10–14
15–19
20–24
25–29
30–34
35–39
∴ Last class interval = 35–39
Are these inclusive or exclusive class intervals?
For example, 19 belongs to the class 10–19, and 20 belongs to the class 20–29.
∴ These are inclusive class intervals.
Are these inclusive or exclusive class intervals?
For example, the intervals can be interpreted as:
10 ≤ x < 20 20 ≤ x < 30 30 ≤ x < 40 ∴ These are exclusive class intervals.[/et_pb_text][/et_pb_column][/et_pb_row][et_pb_row admin_label="SE_Question" _builder_version="4.27.6" _module_preset="default" custom_margin="-50px||||false|false" global_colors_info="{}"][et_pb_column type="4_4" _builder_version="4.27.6" _module_preset="default" global_colors_info="{}"][et_pb_text _builder_version="4.27.6" _module_preset="default" text_font="|300|||||||" text_font_size="18px" custom_padding="0.5%||0.5%|1%|false|false" hover_enabled="0" text_font_size_tablet="17px" text_font_size_phone="16px" text_font_size_last_edited="on|phone" border_radii="on|3px|3px|3px|3px" border_width_all="1px" border_color_all="#0d9488" border_width_all_tablet="1px" border_width_all_phone="2px" border_width_all_last_edited="on|phone" global_colors_info="{}" sticky_enabled="0"]Question 38: Convert the following inclusive class intervals into exclusive class intervals 20–29, 30–39, 40–49
Half of the gap = 1 ÷ 2 = 0.5
Subtract 0.5 from each lower limit and add 0.5 to each upper limit.
| Inclusive Interval | 20–29 | 30–39 | 40–49 |
|---|---|---|---|
| Exclusive Interval | 19.5–29.5 | 29.5–39.5 | 39.5–49.5 |
∴ Exclusive intervals = 19.5–29.5, 29.5–39.5, 39.5–49.5
Correction factor = 1 ÷ 2 = 0.5
Subtract 0.5 from each lower limit and add 0.5 to each upper limit.
∴ Exclusive class intervals 19.5–24.5, 24.5–34.5, 34.5–44.5
∴ Inclusive class intervals 10–19, 20–29, 30–39
Convert them into inclusive class intervals, assuming that the observations are recorded as whole numbers.
∴ Inclusive class intervals 20–29, 30–39, 40–49
| Marks | 0–9 | 10–19 | 20–29 | 30–39 | 40–49 |
|---|---|---|---|---|---|
| Frequency | 3 | 7 | 12 | 9 | 4 |
Number of students
= 12 + 9
= 21
∴ 21 students
| Study Hours | 0–1 | 1–2 | 2–3 | 3–4 | 4–5 |
|---|---|---|---|---|---|
| Frequency | 4 | 8 | 15 | 11 | 6 |
It corresponds to the class interval 2–3.
∴ The class interval 2–3 has the highest frequency.
| Age (years) | 10–19 | 20–29 | 30–39 | 40–49 |
|---|---|---|---|---|
| Frequency | 6 | 14 | 9 | 5 |
Number of participants
= 6 + 14
= 20
| Pages Read | 20–29 | 30–39 | 40–49 | 50–59 | 60–69 |
|---|---|---|---|---|---|
| Frequency | 5 | 9 | 12 | 8 | 6 |
Relevant classes are 40–49, 50–59 and 60–69.
Number of students
= 12 + 8 + 6
= 26
∴ 26 students
| Class Interval | 0–9 | 10–19 | 20–29 | 30–39 |
|---|---|---|---|---|
| Frequency | 6 | 8 | 7 | 11 |
= 6 + 8 + 7 + 11
= 32
But the data set contains only 30 observations.
∴ The frequency table is inconsistent because the total frequency is 32 instead of 30.
| Class Interval | 10–20 | 20–30 | 30–40 |
|---|
Similarly, 30 appears in both 20–30 and 30–40.
Thus, the class intervals overlap and an observation at a boundary cannot be assigned uniquely.
∴ The class intervals are not mutually exclusive.
The total frequency is 4 + 7 + 6 + 9 = 26
But the data set contains only 25 observations.
∴ The table is incorrect because the total frequency exceeds the number of observations by 1.
Class width = 25 − 15 = 10
Half of the class width 10 ÷ 2 = 5
For each class
Lower limit = Class mark − 5
Upper limit = Class mark + 5
| Class Mark | 15 | 25 | 35 | 45 | 55 |
|---|---|---|---|---|---|
| Class Interval | 10–20 | 20–30 | 30–40 | 40–50 | 50–60 |
So Class width = 10
∴ Class intervals = 10–20, 20–30, 30–40, 40–50 and 50–60
Half of the class width 10 ÷ 2 = 5
For class mark 72
Lower limit = 72 − 5 = 67
Upper limit = 72 + 5 = 77
∴ The class interval is 67–77.
Class width = 9.5 − 4.5 = 5
Half of the class width 5 ÷ 2 = 2.5
Subtract 2.5 from and add 2.5 to each class mark.
| Class Mark | 4.5 | 9.5 | 14.5 | 19.5 |
|---|---|---|---|---|
| Class Interval | 2–7 | 7–12 | 12–17 | 17–22 |
∴ Class intervals = 2–7, 7–12, 12–17 and 17–22
For the first class Lower limit = 20 − 20 = 0
∴ Below 20 → 0–20
For the last class Upper limit = 80 + 20 = 100
∴ 80 and Above → 80–100
The complete distribution is 0–20, 20–40, 40–60, 60–80 and 80–100
The last class begins at 75.
Upper limit = 75 + 15 = 90
∴ Upper limit of the last class = 90 years
Less than ¤150, ¤150–¤250, ¤250–¤350 and ¤350–¤450
Assuming equal class widths, find the class mark of the first class after converting it into a bounded class.
The first class ends at ¤150.
Lower limit = ¤150 − ¤100 = ¤50
Thus, the first class is ¤50–¤150.
Class mark = (50 + 150) ÷ 2 = 100
∴ Class mark = ¤100
= 18 + 27 + 25 + 14
= 84
Missing frequency
= 100 − 84
= 16
∴ Missing frequency = 16
| Class Interval | 0–10 | 10–20 | 20–30 | 30–40 |
|---|---|---|---|---|
| Frequency | 7 | f | 15 | 6 |
Find the value of the missing frequency f.
7 + f + 15 + 6 = 40
28 + f = 40
f = 40 − 28
f = 12
∴ f = 12
= 9 + 12 + 15
= 36
Remaining observations
= 52 − 36
= 16
Since the final two classes have equal frequencies
Frequency of each class = 16 ÷ 2 = 8
∴ The frequency of each of the final two classes is 8.
or, x = 28 ÷ 2
or, x = 14
The frequencies are now
12, 14, 28, y, 10
Their total is 80.
12 + 14 + 28 + y + 10 = 80
or, 64 + y = 80
or, y = 80 − 64
or, y = 16
∴ y = 16
11–20, 21–30, 31–40 and 41–50
Correction factor 1 ÷ 2 = 0.5
Subtract 0.5 from each lower limit and add 0.5 to each upper limit.
| Inclusive Class Interval | 11–20 | 21–30 | 31–40 | 41–50 |
|---|---|---|---|---|
| Continuous Class Interval | 10.5–20.5 | 20.5–30.5 | 30.5–40.5 | 40.5–50.5 |
∴ The continuous class intervals are 10.5–20.5, 20.5–30.5, 30.5–40.5 and 40.5–50.5.
Correction factor 1 ÷ 2 = 0.5
For the class 6–10
Lower boundary = 6 − 0.5 = 5.5
Upper boundary = 10 + 0.5 = 10.5
∴ The continuous boundaries are 5.5 and 10.5.
Correction factor 0.1 ÷ 2 = 0.05
For the first class
Lower boundary = 1.0 − 0.05 = 0.95
Upper boundary = 1.4 + 0.05 = 1.45
∴ The continuous class interval is 0.95–1.45.
| Class Interval | 30–39 | 40–49 | 50–59 | 60–69 |
|---|---|---|---|---|
| Frequency | 15 | 22 | 18 | 9 |
Correction factor 1 ÷ 2 = 0.5
Adjust each class by subtracting 0.5 from its lower limit and adding 0.5 to its upper limit.
| Continuous Class Interval | 29.5–39.5 | 39.5–49.5 | 49.5–59.5 | 59.5–69.5 |
|---|---|---|---|---|
| Frequency | 15 | 22 | 18 | 9 |
∴ The continuous class intervals are 29.5–39.5, 39.5–49.5, 49.5–59.5 and 59.5–69.5.

What is Frequency Distribution?
A frequency distribution helps identify patterns, compare values and summarise large amounts of data. It forms the foundation for many statistical concepts such as mean, median, mode, graphs and data interpretation.
Frequency and Frequency Distribution
For example, if the marks of students are:
25, 30, 25, 40, 30, 25
then the frequency of 25 is 3, the frequency of 30 is 2 and the frequency of 40 is 1.
Frequency distributions make it easier to organise raw data and identify repeated values.
Types of Frequency Distribution
1. Ungrouped Frequency Distribution
In an ungrouped frequency distribution, every distinct value is listed separately along with its frequency.
Example:
| Marks | 10 | 15 | 20 |
|---|---|---|---|
| Frequency | 1 | 2 | 3 |
This type is suitable when the number of observations is small or when there are only a few distinct values.
2. Grouped Frequency Distribution
When the data contains many observations or a large range of values, similar values are grouped into class intervals.
Example:
| Class Interval | 0–10 | 10–20 | 20–30 |
|---|---|---|---|
| Frequency | 4 | 8 | 12 |
Grouped frequency distributions make large data sets easier to understand and analyse.
Tally Marks
Each observation is represented by a vertical stroke.
The fifth observation is drawn across the previous four strokes to form a group of five.
Example:
| Value | A | B | C | D |
|---|---|---|---|---|
| Tally Marks | |||| | ||||/ || | || | ||||/ |
| Frequency | 4 | 7 | 2 | 5 |
Using tally marks reduces counting errors and makes it easier to prepare frequency distribution tables, especially when dealing with large sets of raw data.
Class Intervals
A class interval represents a group of values within a specific range. Each observation is placed into the appropriate class interval, and the number of observations in each interval is recorded as its frequency.
For example, the marks of 40 students can be grouped as follows:
| Marks | 0–10 | 10–20 | 20–30 | 30–40 | 40–50 |
|---|---|---|---|---|---|
| Frequency | 3 | 7 | 12 | 10 | 8 |
A good class interval should:
Cover all observations in the data set.
Have a suitable width so that the data remains easy to interpret.
Avoid unnecessary repetition or excessive grouping.
The difference between the upper and lower limits of a class interval is called the class width.
Formula:
Class Width = Upper Class Limit − Lower Class Limit
For example:
Class Interval = 20–30
Class Width = 30 − 20 = 10
Parts of a Frequency Distribution Table
The main parts of a frequency distribution table are:
1. Class Interval
A class interval is a range of values grouped together.
Example:
10–19, 20–29, 30–39
Each observation is placed into one of these intervals.
2. Tally Marks
Tally marks are used to count observations quickly while preparing the frequency table.
The fifth tally mark crosses the previous four marks, making groups of five.
3. Frequency
Frequency represents the number of observations present in a particular class interval.
Example:
| Class Interval | 10–19 | 20–29 | 30–39 | 40–49 |
|---|---|---|---|---|
| Tally Marks | ||||/ || | ||||/ |||| | ||||/ | | ||| |
| Frequency | 7 | 9 | 6 | 3 |
A well-prepared frequency distribution table allows large amounts of data to be summarised clearly and forms the basis for further statistical analysis.
Advantages of Frequency Distribution
A frequency distribution offers several advantages in organising and analysing data effectively.
- It organises raw data into a systematic and meaningful form, making large amounts of information easier to understand.
- It helps identify patterns, trends and repeated values within a data set.
- It makes comparison between different groups of data easier by presenting information in a structured table.
- It helps in calculating statistical measures such as mean, median and mode.
- It provides the foundation for preparing statistical graphs such as bar graphs, histograms and frequency polygons.
- It reduces complex data into a simple format, allowing quick interpretation and analysis.
A properly prepared frequency distribution is an important step in statistical analysis because it transforms unorganised data into a form that can be easily studied and interpreted.

Summary of Frequency Distribution
| Concept | Description |
|---|---|
| Raw Data | Data collected in its original, unorganised form before it is arranged into a table. |
| Frequency | The number of times a particular value or observation occurs in a data set. |
| Frequency Distribution | A systematic arrangement of data showing each value or class interval together with its frequency. |
| Ungrouped Frequency Distribution | Lists every distinct value separately along with its corresponding frequency. |
| Grouped Frequency Distribution | Groups observations into class intervals and records the frequency of each interval. |
| Tally Marks | A quick counting method used while preparing a frequency table. Every fifth observation is represented by a diagonal stroke across the previous four tally marks. |
| Class Interval | A range of values grouped together in a grouped frequency distribution. |
| Lower Class Limit | The smallest value included in a class interval. |
| Upper Class Limit | The largest value included in a class interval. |
| Class Width | The size of a class interval. Formula: Class Width = Upper Class Limit − Lower Class Limit |
| Uses of Frequency Distribution | Organises raw data, simplifies analysis, identifies patterns and forms the basis for statistical calculations and graphs. |

Common Mistakes
- Confusing Frequency with Observation. Students often write the observation itself as the frequency. Remember that an observation is the recorded value, while the frequency is the number of times that value occurs.
- Counting Frequencies Incorrectly. Students sometimes miss repeated observations or count the same observation more than once. Count each observation carefully before preparing the frequency table.
- Preparing an Incorrect Tally Table. Students often forget that every fifth tally mark should be represented by a diagonal stroke across the previous four tally marks. This makes counting easier and reduces errors.
- Ignoring the Total Frequency. The sum of all frequencies should always be equal to the total number of observations in the given data set. Always verify the total after completing the table.
- Confusing Grouped and Ungrouped Frequency Distributions. Students often use class intervals even when the data contains only a few distinct observations. Ungrouped frequency distributions are used for individual observations, whereas grouped frequency distributions are used for large data sets.
- Creating Incorrect Class Intervals. Students sometimes create overlapping class intervals or leave gaps between consecutive intervals. Every observation should belong to exactly one class interval.
- Calculating the Class Width Incorrectly. Students often subtract the lower class limit from the upper class limit without adding 1. For inclusive class intervals, use:
Class Width = Upper Class Limit − Lower Class Limit + 1 - Confusing Class Limits with Class Intervals. Students sometimes identify the entire class interval as the class limit. The lower class limit is the smallest value in the interval, while the upper class limit is the largest value.
- Misinterpreting Frequency Tables. Students often assume that the observation with the largest value has the highest frequency. Always compare the frequency values, not the observations themselves.
- Ignoring Missing Observations. While preparing a frequency table, students sometimes omit observations that appear only once. Every distinct observation must be included in the table.
- Using Unequal Class Widths. Students often prepare grouped frequency distributions with inconsistent class widths, making the data difficult to interpret. Unless specified otherwise, all class intervals should have the same width.
- Failing to Verify the Completed Frequency Table. After preparing a frequency table, students often forget to check whether the frequencies add up to the total number of observations and whether every observation has been included exactly once.

Practice Questions
1, 2, 1, 3, 2, 1, 4, 2, 3, 1, 2, 2, 3, 1, 4
Prepare a frequency table and identify the observation with the highest frequency.
| Observation | A | B | C | D |
|---|---|---|---|---|
| Frequency | 9 | 12 | ? | 8 |
Find the missing frequency.
| Marks | 0–9 | 10–19 | 20–29 | 30–39 |
|---|---|---|---|---|
| Frequency | 4 | 10 | 9 | 7 |
Find:
a) The class interval with the highest frequency.
b) The total number of observations.
Find:
a) Lower class limit
b) Upper class limit
c) Class width
| Age (Years) | 10–19 | 20–29 | 30–39 | 40–49 |
|---|---|---|---|---|
| Frequency | 6 | 11 | 8 | 5 |
Find:
a) The total number of observations.
b) The class interval containing the greatest number of observations.
